CID Seminar EN

In this seminar you will learn what is a secession circuit and how it is described in Verilog.

Keywords:clock,flip-flop, blocking/non-blocking'

Verilog syntax: always, initial, forever

The digital circuits are of two types:

1. Combinational logic circuits (CLC) - can be described either using 'assign' or using '
2. sequential circuits - can be described using only always

Exercise 1

Describe in Verilog a bistable D with the following features:

• active clock signal on the positive front
• synchronous reset signal with the clock, active on the 0 scale

Additional explanation

The most commonly used circuit to synchronize any clock signal is the flip-flop D (also called flip-flop FF). The binary D in this example has the following ports:

• Clk - clock input, active on the positive front
• D - Data entry
• nReset - synchronous clock signal input; nRest active on the 0 field
• Q - circuit output

Remark: The reset signal will always be synchronous with the clock, ie it will change its value from 1 to 0 or vice versa always on the active front of the clock !!!

The description of a RTL verilog in Verilog is only possible using always-type processes, with the sensitivity list at least the positive clock face.

In clock processes, signal values ​​are assigned using the non-blocking assignment (with the operator <=, which in this context means "takes the value", and NOT less than or equal !!!) unlike the processes' always' that describe purely combinational circuits and where assigning new values ​​is done using only the blocking assignment (with operator =).

Exercise 2

Simulate the operation of the bistable D. At the CK input a periodic signal with a period of 6 time units will be applied.

Additional explanation

The clock signal has the following properties:

1. Rectangular signal (like all other digital signals)
2. It's a regular signal
3. It's the only signal in a digital system that's active on the front. All other signals present in a digital system are active on the floor.

The simplest way that a clock signal can be generated in Verilog is by using an initial prcess and forever loop. No instruction is added after the instruction forever, because it will never run.

Exercise 3

The combination circuit in the following figure has a hazard on the output. Describe this circuit in Verilog using a 'assign' statement and an 'always' process and then simulate its operation to highlight the hazard.

Additional explanation

When you use assign - the signal must be declared 'wire' '.

When using alwaysthe signal must be declared.

The hazard (behavior of combinational circuits that is not in accordance with logical algebra) is due to propagation times through logical gates. To highlight this phenomenon, we will introduce the propagation times through gates with the syntax: assign #tp ..., where tp is the propagation time.

Exercise 4

Describe the circuit in the following figure in Verilog and simulate its operation.

Additional explanation

The circuit can be described in two ways:

• separating the combined side from the sequential (using 2 processes always)
• using a single process always

The simulation will highlight the elimination of the hazard on the output.

Exercise 5

Simulate and compare the operation of the following circuits (in the two modules only the type of assignment used: non-blocking or blocking):

Circuit 1:

always @ (posedge clk) begin
    if (nReset == 0) begin
        b <= 0;
        c <= 0;
    end else begin
        b <= a;
        c <= b;
    end
end

Circuit 2:

always @ (posedge clk) begin
    if (nReset == 0) begin
        b = 0;
        c = 0;
    end else begin
        b = a;
        c = b;
    end
end

Note: This example will help you understand the above rule: Always use the non-blocking assignment <= to describe synchronous clock circuits.

Additional explanations

The difference between the blocking and the non-blocking assignment types is as follows: unlike the blocking assignment (=), the non-blocking assignment (<=) does not immediately update the left regression signal, but only the end of the pa