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* LEDG0 intensity, denoted I <sub> LEDG0 </sub> is determined by SW7-SW0 | * LEDG0 intensity, denoted I <sub> LEDG0 </sub> is determined by SW7-SW0 | ||
* The LEDG0-7 intensities respect one of the following relationships (the teacher will assign each of the students one of the following relationships): | * The LEDG0-7 intensities respect one of the following relationships (the teacher will assign each of the students one of the following relationships): | ||
| − | * #I <sub> LEDG0 </sub> & lt; I <sub> LEDG1 </sub> & lt; I <sub> LEDG2 </sub> & lt; I <sub> LEDG3 </sub> & lt; I <sub> LEDG4 </sub> & lt; I <sub> LEDG5 </sub> & lt; I <sub> LEDG6 </sub> & lt; I <sub> LEDG7 </sub> | + | * #I <sub> LEDG0 </sub> < I <sub> LEDG1 </sub> < I <sub> LEDG2 </sub> < I <sub> LEDG3 </sub> < I <sub> LEDG4 </sub> < I <sub> LEDG5 </sub> < I <sub> LEDG6 </sub> < I <sub> LEDG7 </sub> |
| − | * #I <sub> LEDG0 </sub> & gt; I <sub> LEDG1 </sub> & lt; I <sub> LEDG2 </sub> & lt; I <sub> LEDG3 </sub> & lt; I <sub> LEDG4 </sub> & lt; I <sub> LEDG5 </sub> & lt; I <sub> LEDG6 </sub> & lt; I <sub> LEDG7 </sub> | + | * #I <sub> LEDG0 </sub> > I <sub> LEDG1 </sub> < I <sub> LEDG2 </sub> < I <sub> LEDG3 </sub> < I <sub> LEDG4 </sub> < I <sub> LEDG5 </sub> < I <sub> LEDG6 </sub> < I <sub> LEDG7 </sub> |
| − | * #I <sub> LEDG0 </sub> & gt; I <sub> LEDG1 </sub> & gt; I <sub> LEDG2 </sub> & lt; I <sub> LEDG3 </sub> & lt; I <sub> LEDG4 </sub> & lt; I <sub> LEDG5 </sub> & lt; I <sub> LEDG6 </sub> & lt; I <sub> LEDG7 </sub> | + | * #I <sub> LEDG0 </sub> > I <sub> LEDG1 </sub> > I <sub> LEDG2 </sub> < I <sub> LEDG3 </sub> < I <sub> LEDG4 </sub> < I <sub> LEDG5 </sub> < I <sub> LEDG6 </sub> < I <sub> LEDG7 </sub> |
| − | * #I <sub> LEDG0 </sub> & gt; I <sub> LEDG1 </sub> & gt; I <sub> LEDG2 </sub> & gt; I <sub> LEDG3 </sub> & lt; I <sub> LEDG4 </sub> & lt; I <sub> LEDG5 </sub> & lt; I <sub> LEDG6 </sub> & lt; I <sub> LEDG7 </sub> | + | * #I <sub> LEDG0 </sub> > I <sub> LEDG1 </sub> > I <sub> LEDG2 </sub> > I <sub> LEDG3 </sub> < I <sub> LEDG4 </sub> < I <sub> LEDG5 </sub> < I <sub> LEDG6 </sub> < I <sub> LEDG7 </sub> |
| − | * #I <sub> LEDG0 </sub> & gt; I <sub> LEDG1 </sub> & gt; I <sub> LEDG2 </sub> & gt; I <sub> LEDG3 </sub> & gt; I <sub> LEDG4 </sub> & lt; I <sub> LEDG5 </sub> & lt; I <sub> LEDG6 </sub> & lt; I <sub> LEDG7 </sub> | + | * #I <sub> LEDG0 </sub> > I <sub> LEDG1 </sub> > I <sub> LEDG2 </sub> > I <sub> LEDG3 </sub> > I <sub> LEDG4 </sub> < I <sub> LEDG5 </sub> < I <sub> LEDG6 </sub> < I <sub> LEDG7 </sub> |
| − | * #I <sub> LEDG0 </sub> & gt; I <sub> LEDG1 </sub> & gt; I <sub> LEDG2 </sub> & gt; I <sub> LEDG3 </sub> & gt; I <sub> LEDG4 </sub> & gt; I <sub> LEDG5 </sub> & lt; I <sub> LEDG6 </sub> & lt; I <sub> LEDG7 </sub> | + | * #I <sub> LEDG0 </sub> > I <sub> LEDG1 </sub> > I <sub> LEDG2 </sub> > I <sub> LEDG3 </sub> > I <sub> LEDG4 </sub> > I <sub> LEDG5 </sub> < I <sub> LEDG6 </sub> < I <sub> LEDG7 </sub> |
| − | * #I <sub> LEDG0 </sub> & gt; I <sub> LEDG1 </sub> & gt; I <sub> LEDG2 </sub> & gt; I <sub> LEDG3 </sub> & gt; I <sub> LEDG4 </sub> & gt; I <sub> LEDG5 </sub> & gt; I <sub> LEDG6 </sub> & lt; I <sub> LEDG7 </sub> | + | * #I <sub> LEDG0 </sub> > I <sub> LEDG1 </sub> > I <sub> LEDG2 </sub> > I <sub> LEDG3 </sub> > I <sub> LEDG4 </sub> > I <sub> LEDG5 </sub> > I <sub> LEDG6 </sub> < I <sub> LEDG7 </sub> |
| − | * #I <sub> LEDG0 </sub> & gt; I <sub> LEDG1 </sub> & gt; I <sub> LEDG2 </sub> & gt; I <sub> LEDG3 </sub> & gt; I <sub> LEDG4 </sub> & gt; I <sub> LEDG5 </sub> & gt; I <sub> LEDG6 </sub> & gt; I <sub> LEDG7 </sub> | + | * #I <sub> LEDG0 </sub> > I <sub> LEDG1 </sub> > I <sub> LEDG2 </sub> > I <sub> LEDG3 </sub> > I <sub> LEDG4 </sub> > I <sub> LEDG5 </sub> > I <sub> LEDG6 </sub> > I <sub> LEDG7 </sub> |
== Bonus Exercise == | == Bonus Exercise == | ||
Make a circuit that then turns off a led gradually, using a variable fill factor generator. | Make a circuit that then turns off a led gradually, using a variable fill factor generator. | ||
Versiunea de la data 11 aprilie 2018 23:46
Notions and Knowledge Required
- Boolean logic and numbering systems
- Syntax Verilog
- Using the Altera Quartus II Synthesis Program
- List of pins for plate DE1
- Sequential Circuits, Counter
- Pulse generator with variable filling factor
Example
Make a circuit that turns on LEDG7 with a variable intensity controlled by a value set by the SW7-SW0 switches using a variable fill factor signal generator based on an 8-bit counter. The numerator will be described as a separate Verilog mode, and will be instantiated in the signal generator.
Exercise
Build a circuit that instantiates 8 variable fill factor signal generators to form a LEDG7-LEDG0 intensity ramp with the following features:
- LEDG0 intensity, denoted I LEDG0 is determined by SW7-SW0
- The LEDG0-7 intensities respect one of the following relationships (the teacher will assign each of the students one of the following relationships):
- #I LEDG0 < I LEDG1 < I LEDG2 < I LEDG3 < I LEDG4 < I LEDG5 < I LEDG6 < I LEDG7
- #I LEDG0 > I LEDG1 < I LEDG2 < I LEDG3 < I LEDG4 < I LEDG5 < I LEDG6 < I LEDG7
- #I LEDG0 > I LEDG1 > I LEDG2 < I LEDG3 < I LEDG4 < I LEDG5 < I LEDG6 < I LEDG7
- #I LEDG0 > I LEDG1 > I LEDG2 > I LEDG3 < I LEDG4 < I LEDG5 < I LEDG6 < I LEDG7
- #I LEDG0 > I LEDG1 > I LEDG2 > I LEDG3 > I LEDG4 < I LEDG5 < I LEDG6 < I LEDG7
- #I LEDG0 > I LEDG1 > I LEDG2 > I LEDG3 > I LEDG4 > I LEDG5 < I LEDG6 < I LEDG7
- #I LEDG0 > I LEDG1 > I LEDG2 > I LEDG3 > I LEDG4 > I LEDG5 > I LEDG6 < I LEDG7
- #I LEDG0 > I LEDG1 > I LEDG2 > I LEDG3 > I LEDG4 > I LEDG5 > I LEDG6 > I LEDG7
Bonus Exercise
Make a circuit that then turns off a led gradually, using a variable fill factor generator.
